198. House Robber
You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will automatically contact the police if two adjacent houses were broken into on the same night.
Given a list of non-negative integers representing the amount of money of each house, determine the maximum amount of money you can rob tonight without alerting the police.
Example 1:
Input: [1,2,3,1]
Output: 4
Explanation: Rob house 1 (money = 1) and then rob house 3 (money = 3).
Total amount you can rob = 1 + 3 = 4.
Example 2:
Input: [2,7,9,3,1]
Output: 12
Explanation: Rob house 1 (money = 2), rob house 3 (money = 9) and rob house 5 (money = 1).
Total amount you can rob = 2 + 9 + 1 = 12.
class Solution(object):
def rob(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
if nums == []:
return 0
dy = []
for i in range(len(nums)):
if i == 0:
dy.append(nums[i])
elif i == 1:
dy.append(nums[i] if nums[i] > nums[i-1] else nums[i-1])
else:
temp = nums[i] + dy[i-2]
print(dy)
print(i)
dy.append( temp if temp > dy[i-1] else dy[i-1])
return dy[-1]
leetcode record
请多多指教。
文章标题:198. House Robber
本文作者:顺强
发布时间:2019-08-18, 23:59:00
原始链接:http://shunqiang.ml/leetcode-198-house-rob/版权声明: "署名-非商用-相同方式共享 4.0" 转载请保留原文链接及作者。