88. Merge Sorted Array

  1. 发现一个优化的方法

Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.

Note:

The number of elements initialized in nums1 and nums2 are m and n respectively.
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2.

Example:
Input:
nums1 = [1,2,3,0,0,0], m = 3
nums2 = [2,5,6], n = 3

Output: [1,2,2,3,5,6]

解题思路:
使用插入排序的方法,将 nums2 中每个元素插入到 nums1 中

class Solution(object):
    def merge(self, nums1, m, nums2, n):
        """
        :type nums1: List[int]
        :type m: int
        :type nums2: List[int]
        :type n: int
        :rtype: None Do not return anything, modify nums1 in-place instead.
        """
        # index = 0
        i, j = 0, 0
        for i in range(n):
            if nums2[i] < nums1[m-1]:
                # temp = nums2[i]
                j = m - 1
                while j >= 0 and nums2[i] < nums1[j]:
                    # print(nums1)
                    nums1[j+1] = nums1[j]
                    j -= 1
                nums1[j+1] = nums2[i]
            else:
                nums1[m] = nums2[i]
            m += 1
        return nums1

发现一个优化的方法


请多多指教。

文章标题:88. Merge Sorted Array

本文作者:顺强

发布时间:2019-04-26, 23:59:00

原始链接:http://shunqiang.ml/leetcode-88-merge-sorted-array/

版权声明: "署名-非商用-相同方式共享 4.0" 转载请保留原文链接及作者。

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